Wireshark mailing list archives
Re: bitwise operating gives syntax error. + displaying a slice.
From: Jaap Keuter <jaap.keuter () xs4all nl>
Date: Mon, 09 Apr 2012 17:50:31 +0200
Hi, Are you trying capture or display filters here? The capture file expression part "ip[0] & 0" would always yield 0. Thanks, Jaap On 04/08/2012 05:37 PM, Marilo wrote:
I am having trouble trying to get the bitwise operator to function here without a syntax error This works C:\sdf>tshark -r asdf2 "ip[0]==45" but when I put a bitwise AND in there, I get a syntax error C:\sdf>tshark -r asdf2 "ip[0]&0==45" tshark: Syntax error. Note: That display filter code looks like a valid capture filter; maybe you mixed them up? C:\sdf> Also where in the manual does it speak about this? And it'd be really useful in debugging a filter, if I could display, say, ip[0] or ip[0]<<2 Is that possible and is it possible to only display ip[0] or tcp[12] or whatever slice, of a packet?
___________________________________________________________________________ Sent via: Wireshark-users mailing list <wireshark-users () wireshark org> Archives: http://www.wireshark.org/lists/wireshark-users Unsubscribe: https://wireshark.org/mailman/options/wireshark-users mailto:wireshark-users-request () wireshark org?subject=unsubscribe
Current thread:
- bitwise operating gives syntax error. + displaying a slice. Marilo (Apr 08)
- Re: bitwise operating gives syntax error. + displaying a slice. Jaap Keuter (Apr 09)
- Re: bitwise operating gives syntax error. + displaying a slice. Marilo (Apr 09)
- Re: bitwise operating gives syntax error. + displaying a slice. Sam Roberts (Apr 09)
- Re: bitwise operating gives syntax error. + displaying a slice. Marilo (Apr 09)
- Re: bitwise operating gives syntax error. + displaying a slice. Sake Blok (Apr 09)
- Re: bitwise operating gives syntax error. + displaying a slice. Jaap Keuter (Apr 09)