WebApp Sec mailing list archives
Re: MD5 math question
From: Charles Miller <cmiller () pastiche org>
Date: Wed, 4 Jan 2006 14:54:14 +1100
On 04/01/2006, at 12:18 PM, Jeff Robertson wrote:
Assume that a password between 1 and 24 ASCII characters was stored asan MD5 hash. No salt. What is the probability that someone cracking the password will find not the password that the user originally chose, buta different password that happens to collide with it? Intuitively it seems so unlikely that you wouldn't ever expect to see it. But what is the probability really?
From my back-of-the-envelope calculation, your intuition is misplaced. :)
Even if you assume only 6 bits of variance per password character (which is just a-zA-Z0-9 plus two punctuation chars), that's 2^144 possible 24-character passwords. MD5 is a 128 bit hash, so that's 2^16 passwords for every hash value, or only a 1 in 65,000 chance that the first matching hash you come across in the password space is, in fact, the correct password.
And that's only if you assume the original password lives inside [a- zA-Z0-9.!]{24}, not the "1-24 ASCII characters" of the original question.
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Current thread:
- MD5 math question Jeff Robertson (Jan 03)
- Re: MD5 math question Chris Varenhorst (Jan 03)
- Re: MD5 math question Tim (Jan 03)
- RE: MD5 math question Vipul Kumra (Jan 04)
- Memo: Re: MD5 math question tim . m . james (Jan 04)
- Re: MD5 math question Charles Miller (Jan 05)
- Re: MD5 math question exon (Jan 06)
- Re: MD5 math question Tim (Jan 06)
- Re: MD5 math question exon (Jan 06)
- Re: MD5 math question Tim (Jan 07)
- Re: MD5 math question exon (Jan 07)
- Re: MD5 math question Tim (Jan 07)
- Re: MD5 math question exon (Jan 06)
- Re: MD5 math question Charles Miller (Jan 06)
- <Possible follow-ups>
- FW: RE: MD5 math question Vipul Kumra (Jan 04)
- Re: FW: RE: MD5 math question Chuck (Jan 06)
- RE: MD5 math question Navroz Shariff (Jan 04)