Snort mailing list archives

Re: very simple question about $ operand


From: Martin Roesch <roesch () sourcefire com>
Date: Wed, 26 Jan 2005 11:26:19 -0500

It's on pages 13-14 of the manual under the Variables section. The $ operator let's the parser know that you're referring to a predefined variable. For example:

var FOO 10.1.1.0/24

alert tcp any any -> $FOO 1234 (msg: "foo";)

On Jan 25, 2005, at 11:59 AM, gsr4 () excite com wrote:



I have searched the snort users manual and I cannot find the definition or meaning of the $ operand. What does this mean and why is it assumed we are supposed to know this?





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