Snort mailing list archives
Re: very simple question about $ operand
From: Martin Roesch <roesch () sourcefire com>
Date: Wed, 26 Jan 2005 11:26:19 -0500
It's on pages 13-14 of the manual under the Variables section. The $ operator let's the parser know that you're referring to a predefined variable. For example:
var FOO 10.1.1.0/24 alert tcp any any -> $FOO 1234 (msg: "foo";) On Jan 25, 2005, at 11:59 AM, gsr4 () excite com wrote:
I have searched the snort users manual and I cannot find the definition or meaning of the $ operand. What does this mean and why is it assumed we are supposed to know this?Join Excite! - http://www.excite.com The most personalized portal on the Web!
-- Martin Roesch - Founder/CTO, Sourcefire Inc. - +1-410-290-1616 Sourcefire - Discover. Determine. Defend. roesch () sourcefire com - http://www.sourcefire.com Snort: Open Source Network IDS - http://www.snort.org ------------------------------------------------------- This SF.Net email is sponsored by: IntelliVIEW -- Interactive Reporting Tool for open source databases. Create drag-&-drop reports. Save time by over 75%! Publish reports on the web. Export to DOC, XLS, RTF, etc. Download a FREE copy at http://www.intelliview.com/go/osdn_nl _______________________________________________ Snort-users mailing list Snort-users () lists sourceforge net Go to this URL to change user options or unsubscribe: https://lists.sourceforge.net/lists/listinfo/snort-users Snort-users list archive: http://www.geocrawler.com/redir-sf.php3?list=snort-users
Current thread:
- very simple question about $ operand gsr4 () excite com (Jan 26)
- Re: very simple question about $ operand Alex Butcher, ISC/ISYS (Jan 26)
- Re: very simple question about $ operand Martin Roesch (Jan 26)