nanog mailing list archives

Re: The 100 Gbit/s problem in your network


From: Neil Harris <neil () tonal clara co uk>
Date: Tue, 12 Feb 2013 15:32:11 +0000

On 12/02/13 14:14, fredrik danerklint wrote:
Just to clarify, Patrick is right here.


Assumptions:

All the movies is 120 minuters long. Each movie has an average bitrate of 50 Mbit/s.

(50 Mbit/s / 8 (bits) * 7 200 (2 hours) / 1000 (MB) = 45 GB).


That means that the storage capacity for the movies is going to be:

10 000 000 * 45 (GB) / 1000 (TB) / 1000 (PB) = 450 PB of storage.


Some of you might want to raise your hand to say that this quality of
the movie is to good. Ok, so we make it 10 times smaller to 5 Mbit/s
in average:

450 PB / 10 = 45 PB or 45 000 TB.


If we are using 800 GB SSD drives:

45 000 TB / 0,8 TB = 56 250 SSD drives!

(And we don't have any kind of backup of the content here. That need
more SSD drives as well. And don't forget the power consumption).


So over to the streaming part.

10 000 000 Customers watching, each with a bandwidth of 5 Mbit/s =
50 000 000 Mbit/s / 1000 (Gbit/s) = 50 000 Gbit/s.


We only need 500 * 100 Gbit/s connections to solve this kind of
demand. For each ISP around the world with 10 000 000 Millions
of customers.


Will TLMC be able to solve the 100k users watching 10 different
movies? Yes.

Will TLMC be able to solve the other 10 Million watching 10 Million
movies. No, since your network can not handle this kind of load in
the first place.



Fortunately, we have some fascinating recent research on exactly this:

http://www.land.ufrj.br/~classes/coppe-redes-2012/trabalho/youtube_imc07.pdf

-- N.












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