Security Basics mailing list archives

RE: 51% can be enough Was: Wiping a drive


From: Alexander Klimov <alserkli () inbox ru>
Date: Sat, 18 Oct 2008 00:34:53 +0200 (IST)

On Thu, 16 Oct 2008, Olatunji Nowlin wrote:
I think he is stating that there is a 49% of correct recovery of
EACH individual bit on the drive.  My math could be rusty after all
these years, but that would mean the chance of getting any two bits
correct is 0.49*0.49 or 0.24 (24%),

I suspect you missed the point: each bit is noisy (low SNR), but if
you have many copies of the same bit, then you can significantly
increase SNR (see <http://en.wikipedia.org/wiki/Repetition_code>).

-- 
Regards,
ASK


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