Metasploit mailing list archives
question on Apple Quicktime RTSP bind/attach process
From: adrian at inetb.com (base)
Date: Tue, 27 Nov 2007 10:58:23 -0600
The payload in question is a standard bindshell, meaning it listens on the victims machine for an incoming connection. Only the initial exploitation process involves the target connecting to the host machine. If these facts were not terribly obvious to you, you've gotten far ahead of yourself and should read up on the basics like suggested earlier in this thread. you will find a wealth of information from older projects and papers detailing basic shellcode and exploitation. Aleph 1s paper, 'smashing the stack for fun & profit' is still helpful for a beginner even though it is over a decade old. Jeffs wrote:
Are you sure the payload opens a listening socket on the *victim's* machine? * The way I understand that sploit to work is it allows the attacker to listen for a connection whilst at the same time listening on another port (4444) for a connection from the victims machine. The sploit creates an RTSP server that waits for a connection, then sends code to the victim having them contact the attacher's machine. Kurt Grutzmacher wrote:You should learn more about buffer overflows before you get too deep into any code. There are a ton of resources on the web that a quick google will direct you towards. But to quickly answer your question, the payload shellcode provides the instructions to open a listener socket on port 4444 on the victim's machine that you connect to with netcat. It's assembly code because the overflow allowed us to execute it. The script you linked to just uses the shellcode generated by metasploit. It doesn't integrate within the framework. An exploit has been written and is available in the current svn trunk. On Tue, Nov 27, 2007 at 09:20:31AM -0500, Jeffs wrote:Regarding http://www.securityfocus.com/data/vulnerabilities/exploits/26549-uni.py which is the Apple QuickTime RTSP Response Header Remote Stack Based Buffer Overflow Vulnerability -- as a newbie I have a simple question. I understand the code behind the exploit in theory, but am confused about how one would successfully attach or bind to the process that is sitting at port 4444 (assuming you used that value as per the code) to get the reverse shell? Netcat wouldn't do it because there is no netcat process being sent to the attacking machine. If you could integrate it into metasploit then I understand you would have a "session". But this is a python script. How does one integrate it into metasploit if at all. If not, how does the attacking machine attach to the bind process coming in on port 4444? Thank you from a newbie
Current thread:
- question on Apple Quicktime RTSP bind/attach process Jeffs (Nov 27)
- question on Apple Quicktime RTSP bind/attach process Kurt Grutzmacher (Nov 27)
- question on Apple Quicktime RTSP bind/attach process Jeffs (Nov 27)
- question on Apple Quicktime RTSP bind/attach process base (Nov 27)
- question on Apple Quicktime RTSP bind/attach process Jeffs (Nov 27)
- question on Apple Quicktime RTSP bind/attach process Pusscat (Nov 27)
- question on Apple Quicktime RTSP bind/attach process Kurt Grutzmacher (Nov 27)
- question on Apple Quicktime RTSP bind/attach process Jeffs (Nov 27)
- question on Apple Quicktime RTSP bind/attach process Kurt Grutzmacher (Nov 27)