Re: Administrivia: List Announcement

["Edinelson Keiji Shimokawa" <dev () pop com br>]

Benjamin A. Okopnik disse: 

>         l1 = strlen(p1);
>         s1 = sizeof(p1);
>         l2 = strlen(p2);
>         s2 = sizeof(p2);

I think that there we need to code: 

>         l1 = strlen(buf1);
>         s1 = sizeof(buf1);
>         l2 = strlen(buf2);
>         s2 = sizeof(buf2);

but, I coded and the results:
# ./a.out `perl -e 'print "A" x 251;print " "; print "B" x 251'`
strlen1: 251 sizeof1: 4
strlen2: 251 sizeof2: 4
# ./a.out `perl -e 'print "A" x 252;print " "; print "B" x 251'`
strlen1: 254 sizeof1: 4
strlen2: 251 sizeof2: 4
# ./a.out `perl -e 'print "A" x 253;print " "; print "B" x 251'`
Segmentation fault
# ./a.out `perl -e 'print "A" x 252;print " "; print "B" x 252'`
strlen1: 254 sizeof1: 4
strlen2: 254 sizeof2: 4
# ./a.out `perl -e 'print "A" x 251;print " "; print "B" x 252'`
strlen1: 251 sizeof1: 4
strlen2: 254 sizeof2: 4
# ./a.out `perl -e 'print "A" x 252;print " "; print "B" x 253'`
strlen1: 254 sizeof1: 4
strlen2: 254 sizeof2: 4
# ./a.out `perl -e 'print "A" x 252;print " "; print "B" x 254'`
strlen1: 254 sizeof1: 4
strlen2: 254 sizeof2: 4
# ./a.out `perl -e 'print "A" x 252;print " "; print "B" x 255'`
strlen1: 254 sizeof1: 4
strlen2: 254 sizeof2: 4 

mmm... it seems that buf2 overflowed 2 bytes. try other sizes for SIZE.
I have tried 248 and 250. it's amazing that doesn't sigfaults.
seems a very special condition. 


Edinelson Keiji Shimokawa.
A jedi prentice owned by Dark Force. 




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