Snort mailing list archives

missing declaration makes 1.8.6 to segfault


From: "Federico Lombardo" <egopfe () hotmail com>
Date: Tue, 9 Apr 2002 16:55:04 +0200

I've discovered that is you wrote this rule:

rulename $VAR1 any -> $VAR2 any

if you don't declare $VAR1 snort returns an error,
if you don't declare $VAR2 snort segfaults.

Cheers, Federico


- Nemo me impune lacessit -
         Ego^pFe @*NET

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