Re: Hardcore -r question

[John Sage <jsage () finchhaven com>]

Mark:

Awesome!

Of course!

I hadn't gotten to thinking it through that far. Knew there had to be a 
reason.

Just to fill in completely:

  111  =    0x6F
62319  =  0xF36F

Thnx..

- John

Mark Evans wrote:

> note that 111 in binary is          01101111
> and that 62319 in binary is 1111001101101111
>
> so if you just look at the binary then they
> both match on the 2nd byte - the one that [3:1]
> looks at.
>
> it would have matched a whole load of other
> packets that ended 01101111 if you had received 
> any.
>
> as i understand it (ymmv)
>
> cheers,



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