Penetration Testing mailing list archives
Re: RE: Discovering network subnets
From: nobody () nowhere com
Date: 21 Aug 2005 22:43:28 -0000
Nope. According to your example, you have defined two networks: 10.0.0.0/23 10.0.1.0/23 10.0.{0,1}.255 would be the broadcast address for each one 10.0.{0,1}.0 would <still> be the network address itself - not a host address There's only one valid application/use of .0 as a host address - check http://www.ietf.org/rfc/rfc3021.txt?number=3021 - which also includes a lot if interesting pointers to other RFCs and addressing rules for IPv4. Considering the answers Hannibal got, I tend to think the packet to .0 got translated by a route connected to that network to an L2 broadcast - and more than one host received it and replied to it. So actually those open ports could come from one, two, or three different hosts. ------------------------------------------------------------------------------ FREE WHITE PAPER - Wireless LAN Security: What Hackers Know That You Don't Learn the hacker's secrets that compromise wireless LANs. Secure your WLAN by understanding these threats, available hacking tools and proven countermeasures. Defend your WLAN against man-in-the-Middle attacks and session hijacking, denial-of-service, rogue access points, identity thefts and MAC spoofing. Request your complimentary white paper at: http://www.securityfocus.com/sponsor/AirDefense_pen-test_050801 -------------------------------------------------------------------------------
Current thread:
- Discovering network subnets hannibal blog (Aug 20)
- Re: Discovering network subnets Craig Holmes (Aug 21)
- Re: Discovering network subnets Kelly Scroggins (Aug 21)
- Re: Discovering network subnets Kelly Scroggins (Aug 21)
- <Possible follow-ups>
- RE: Discovering network subnets Payton, Zack (Aug 20)
- RE: Discovering network subnets Timothy Dillman (Aug 21)
- Re: RE: Discovering network subnets nobody (Aug 21)
- Re: RE: Discovering network subnets chad (Aug 22)
- Re: RE: Discovering network subnets hannibal blog (Aug 23)