Re: Request for Comments on a topological address block for N. Calif.

[Vadim Antonov <avg () sprint net>]

That is not the new question -- i was trying to obtain the block
equal to 8k class Cs a year ago -- unsuccessfully.

How about treating Sprint's allocations as allocations for 10
providers in different geographical areas?

--vadim

Sean,

Currently Sprint receives the largest sized CIDR block the InterNIC
is permitted to allocate.  If you have a requirement for an even
larger block than please submit the justification and I will be glad
to pass it onto the IANA for approval.

Kim Hubbard
InterNIC Registry


> Unfortunately, the allocations we've been getting haven't
> been very big, and so we end up having to introduce things
> as long as 17 bits to the world, where we might have only
> had to announce /16s and /15s with a larger delegation
> from a registry.
>
> Block Name    Total Free Used                   Free Blocks
>                Cs    Cs         1   2   4   8  16  32  64 128 256 512 1024
> --------------------------------------------------------------------------
> East           2863  233  91%   1           1       1   1   1
> West           2176   51  97%   1   1           1   1
> South          2176   47  97%   1   1   1   1       1
> North          1920  218  88%       1       1   1       1   1
> NorthEast      1408  211  85%   1   1           1       1   1
> SouthWest       768  173  77%   1       1   1       1       1
> NYSERNet        512  129  74%   1                           1
> ICM-Atlantic    128  122   4%       1       1   1   1   1
> --------------------------------------------------------------------------
>         TOTAL 11951 1184  90%   6   5   2   5   4   5   4   5
>
>
> So, beacause we are clever and do a mix of provider-based
> and geography-based allocation (but it is a mix of both,
> with an emphasis on the provider part), we end up with
> blocks that are starving, but a single huge allocation that
> isn't full enough to have a new large allocation done by the
> registry.
>
>       Sean.