Wireshark mailing list archives
Re: Lua converting a UINT64 to hex
From: Tony Trinh <tony19 () gmail com>
Date: Mon, 19 Nov 2012 19:42:24 -0600
On Mon, Nov 19, 2012 at 10:07 AM, Zadik, Maayan <mzadik () qti qualcomm com> wrote:
Hi all, I'm trying to create a validation script on my protocol dissector. My dissector is written in C and the validation script is obviously in
Lua.
I have this field that is 64bits long. I'm trying to read it in my Lua
script
local data_f = Field.new("my_protocol.data") I'm trying ti convert it to a hex string local data = data_f() ... Local s = string.format("%X", data.value) and get the following error: bad argument #2 to 'format' (number expected, got userdata) is there no way to retrieve the value of a UINT64 field in Lua? Maybe breaking it to 2 UINT32 or something?
In your code, the variable "data" is actually a list of instances of the field in the packet (each represented by a FieldInfo object). To get the values, you'll need to iterate the list: for _,fieldinfo in pairs( data ) do print( fieldinfo.label, fieldinfo.value ) end
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Current thread:
- Lua converting a UINT64 to hex Zadik, Maayan (Nov 19)
- Re: Lua converting a UINT64 to hex Tony Trinh (Nov 19)
- Re: Lua converting a UINT64 to hex Tony Trinh (Nov 19)
- Re: Lua converting a UINT64 to hex Tony Trinh (Nov 19)
- Re: Lua converting a UINT64 to hex Tony Trinh (Nov 19)
- Re: Lua converting a UINT64 to hex Stig Bjørlykke (Nov 20)
- Re: Lua converting a UINT64 to hex Tony Trinh (Nov 19)