Wireshark mailing list archives

Re: mean opinion score


From: "RUOFF, LARS (LARS)** CTR **" <lars.ruoff () alcatel-lucent com>
Date: Tue, 13 Apr 2010 11:29:33 +0200

Hi,
That's true.
But just for completeness, know that there is also another ITU-T recommendation, "G.107 - The E-model, a computational 
model for use in transmission planning" (not freely available from ITU-T though), which describes how to calculate a 
MOS from objectively measured parameters.
These include network- (loss, delay, jitter) as well as device- (TELR, ELR etc.) and environment- (noise etc.) specific 
parameters.
At least for the network related impairments, a network analysis tool like Wireshark could help in principle in that it 
could provide these calculation, assuming the other parameters stay constant and can be used with reasonable default 
values. 

Regards,
Lars Ruoff

-----Original Message-----
From: wireshark-users-bounces () wireshark org 
[mailto:wireshark-users-bounces () wireshark org] On Behalf Of Guy Harris
Sent: lundi 12 avril 2010 20:40
To: Community support list for Wireshark
Subject: Re: [Wireshark-users] mean opinion score


On Apr 12, 2010, at 8:16 AM, ankur aggarwal wrote:

Can anybody help me in finding MOS through wireshark or any 
other s/w which work on my intranet. (offline mode).

Wireshark is software, not a human being, and thus cannot 
itself generate a mean opinion score; the same applies to any 
other software.

The mean opinion score is calculated based on *subjective* 
evaluations of sound quality by human listeners; see the 
Wikipedia article:

      http://en.wikipedia.org/wiki/Mean_opinion_score

and the ITU-T recommendation to which it refers, P.80:

      http://www.itu.int/rec/T-REC-P.800-199608-I/en

You could, at best, have Wireshark play back the audio and 
have various listeners evaluate it, and then calculate the 
MOS based on their evaluations.
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