nanog mailing list archives
Re: Satellite latency
From: "Brett Frankenberger" <rbf () rbfnet com>
Date: Tue, 26 Feb 2002 21:53:28 -0600 (CST)
Remember that a geosynchronous satellte must orbit the equator. Let's say for the sake of argument it's over mexico, you're in New York, and the downlink station is in San Diego. The 36,000 is the distance straight "down" to mexico, It's probably more like 50,000 to New York, and 45,000 to San Diego.
The radius of the earth is about 6400km. Geostationary orbit is, as you note, 36000km above the equator. The path from the satellite to the North Pole is the hypotenuse of a right triangle with legs of 6400km and (6400+36000)km. That gives a distance from the North Pole to the satellite of 43000km. It's reasonable to conclude that the distance from either New York or San Diego is less than that. -- Brett
Current thread:
- Re: Satellite latency Steven M. Bellovin (Feb 26)
- Re: Satellite latency Leo Bicknell (Feb 26)
- Re: Satellite latency Brett Frankenberger (Feb 26)
- Re: Satellite latency Michael Painter (Feb 27)
- Re: Satellite latency Jim Mercer (Feb 27)
- Re: Satellite latency Valdis . Kletnieks (Feb 27)
- Re: Satellite latency Jim Mercer (Feb 27)
- Re: Satellite latency Joe Abley (Feb 27)
- Re: Satellite latency Valdis . Kletnieks (Feb 27)
- RE: Satellite latency Tony Hain (Feb 27)
- Re: Satellite latency Leo Bicknell (Feb 26)
- <Possible follow-ups>
- RE: Satellite latency Rowland, Alan D (Feb 27)
- Re: Satellite latency Dickson, Brian (Feb 27)
- Re: Satellite latency Iljitsch van Beijnum (Feb 27)
- Re: Satellite latency Simon Lyall (Feb 27)
- Re: Satellite latency Iljitsch van Beijnum (Feb 27)